Saturday, January 10, 2009

Gateway Arch

My friend, Maytham, just came from St.Louis, Missouri. He told me about his visit to The Gateway Arch and showed me some pictures of it. I have heard of the structure before, but I never knew that you can actually take a tour INSIDE the arch. Isn't that amazing. Here are some pictures I found online:

From wikipedia: Mathematical equation of the arch.

y = A \left( \cosh \frac {Cx}{L} - 1 \right),

or, equivalently

x = \frac {L}{C} \cosh^{-1} \left( 1 + \frac {y}{A} \right),

where

A = \frac {f_c} {Q_b/Q_t - 1} = 68.7672

C = \cosh^{-1} \frac {Q_b}{Q_t} = 3.0022

fc = maximum height of centroid (in feet) = 625.0925

Qb = maximum cross sectional area of arch at base (in sq. feet) = 1262.6651

Qt = minimum cross sectional area of arch at top (in sq. feet) = 125.1406

L = half width of centroid at the base (in feet) = 299.2239


AMAZING!!!!!!!!!!!!!!!!


3 click here to leave a comment:

  1. woooooooooow
    really,really....
    amazing,,,
    how did they build it!!!!!!!!!!
    i'm sure that it's gonna be a good place to visit in the future
    ...

    ReplyDelete
  2. Hashim Alhamad,

    Hello, my name is Angela Wade. I'm a student at Miami University of Ohio. I am writing to ask permission to use your above image of the St. Louis Arch. I'd like to use your image in an article to be published in the Ohio Journal of School Mathematics to help students see connections between mathematics and the real world. Your image would be quite useful in this regard.

    Please let me know if I have your permission to use the iamge. I'll include your name and a link to your web page in my article. Also, please let me know if I would be able to crop your image. Let me know if you have any comments, questions, or concerns about this. If you could e-mail your resonpse to wadeam2@muohio.edu that would be ver helpful.

    Best Wishes,
    Angela Wade

    ReplyDelete
  3. I am about to send you an email :)

    ReplyDelete